5t^2-1t-40=0

Solution for 5t^2-1t-40=0 equation:

5t^2-1t-40=0

a = 5; b = -1; c = -40;
Δ = b2-4ac
Δ = -12-4·5·(-40)
Δ = 801
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{801}=\sqrt{9*89}=\sqrt{9}*\sqrt{89}=3\sqrt{89}$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-3\sqrt{89}}{2*5}=\frac{1-3\sqrt{89}}{10}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+3\sqrt{89}}{2*5}=\frac{1+3\sqrt{89}}{10}
$